lnd.xprv/routing/integrated_routing_test.go
Joost Jager 7fc1938f10
routing: payment splitting pre-check
This commit reverts cb4cd49dc8d3b0255afe9ff29af9c46c2dbb2c98 to bring
back the insufficient local balance failure.

Distinguishing betweeen this failure and a regular "no route" failure
prevents meaningless htlcs from being sent out.
2020-04-18 08:30:26 +02:00

301 lines
8.1 KiB
Go

package routing
import (
"testing"
"github.com/btcsuite/btcutil"
"github.com/lightningnetwork/lnd/lnwire"
)
// TestProbabilityExtrapolation tests that probabilities for tried channels are
// extrapolated to untried channels. This is a way to improve pathfinding
// success by steering away from bad nodes.
func TestProbabilityExtrapolation(t *testing.T) {
ctx := newIntegratedRoutingContext(t)
// Create the following network of nodes:
// source -> expensiveNode (charges routing fee) -> target
// source -> intermediate1 (free routing) -> intermediate(1-10) (free routing) -> target
g := ctx.graph
const expensiveNodeID = 3
expensiveNode := newMockNode(expensiveNodeID)
expensiveNode.baseFee = 10000
g.addNode(expensiveNode)
g.addChannel(100, sourceNodeID, expensiveNodeID, 100000)
g.addChannel(101, targetNodeID, expensiveNodeID, 100000)
const intermediate1NodeID = 4
intermediate1 := newMockNode(intermediate1NodeID)
g.addNode(intermediate1)
g.addChannel(102, sourceNodeID, intermediate1NodeID, 100000)
for i := 0; i < 10; i++ {
imNodeID := byte(10 + i)
imNode := newMockNode(imNodeID)
g.addNode(imNode)
g.addChannel(uint64(200+i), imNodeID, targetNodeID, 100000)
g.addChannel(uint64(300+i), imNodeID, intermediate1NodeID, 100000)
// The channels from intermediate1 all have insufficient balance.
g.nodes[intermediate1.pubkey].channels[imNode.pubkey].balance = 0
}
// It is expected that pathfinding will try to explore the routes via
// intermediate1 first, because those are free. But as failures happen,
// the node probability of intermediate1 will go down in favor of the
// paid route via expensiveNode.
//
// The exact number of attempts required is dependent on mission control
// config. For this test, it would have been enough to only assert that
// we are not trying all routes via intermediate1. However, we do assert
// a specific number of attempts to safe-guard against accidental
// modifications anywhere in the chain of components that is involved in
// this test.
attempts, err := ctx.testPayment(1)
if err != nil {
t.Fatalf("payment failed: %v", err)
}
if len(attempts) != 5 {
t.Fatalf("expected 5 attempts, but needed %v", len(attempts))
}
// If we use a static value for the node probability (no extrapolation
// of data from other channels), all ten bad channels will be tried
// first before switching to the paid channel.
ctx.mcCfg.AprioriWeight = 1
attempts, err = ctx.testPayment(1)
if err != nil {
t.Fatalf("payment failed: %v", err)
}
if len(attempts) != 11 {
t.Fatalf("expected 11 attempts, but needed %v", len(attempts))
}
}
type mppSendTestCase struct {
name string
amt btcutil.Amount
expectedAttempts int
// expectedSuccesses is a list of htlcs that made it to the receiver,
// regardless of whether the final set became complete or not.
expectedSuccesses []expectedHtlcSuccess
graph func(g *mockGraph)
expectedFailure bool
maxShards uint32
}
const (
chanSourceIm1 = 13
chanIm1Target = 32
chanSourceIm2 = 14
chanIm2Target = 42
)
func onePathGraph(g *mockGraph) {
// Create the following network of nodes:
// source -> intermediate1 -> target
const im1NodeID = 3
intermediate1 := newMockNode(im1NodeID)
g.addNode(intermediate1)
g.addChannel(chanSourceIm1, sourceNodeID, im1NodeID, 200000)
g.addChannel(chanIm1Target, targetNodeID, im1NodeID, 100000)
}
func twoPathGraph(g *mockGraph, capacityOut, capacityIn btcutil.Amount) {
// Create the following network of nodes:
// source -> intermediate1 -> target
// source -> intermediate2 -> target
const im1NodeID = 3
intermediate1 := newMockNode(im1NodeID)
g.addNode(intermediate1)
const im2NodeID = 4
intermediate2 := newMockNode(im2NodeID)
g.addNode(intermediate2)
g.addChannel(chanSourceIm1, sourceNodeID, im1NodeID, capacityOut)
g.addChannel(chanSourceIm2, sourceNodeID, im2NodeID, capacityOut)
g.addChannel(chanIm1Target, targetNodeID, im1NodeID, capacityIn)
g.addChannel(chanIm2Target, targetNodeID, im2NodeID, capacityIn)
}
var mppTestCases = []mppSendTestCase{
// Test a two-path graph with sufficient liquidity. It is expected that
// pathfinding will try first try to send the full amount via the two
// available routes. When that fails, it will half the amount to 35k sat
// and retry. That attempt reaches the target successfully. Then the
// same route is tried again. Because the channel only had 50k sat, it
// will fail. Finally the second route is tried for 35k and it succeeds
// too. Mpp payment complete.
{
name: "sufficient inbound",
graph: func(g *mockGraph) {
twoPathGraph(g, 200000, 100000)
},
amt: 70000,
expectedAttempts: 5,
expectedSuccesses: []expectedHtlcSuccess{
{
amt: 35000,
chans: []uint64{chanSourceIm1, chanIm1Target},
},
{
amt: 35000,
chans: []uint64{chanSourceIm2, chanIm2Target},
},
},
maxShards: 1000,
},
// Test that a cap on the max htlcs makes it impossible to pay.
{
name: "no splitting",
graph: func(g *mockGraph) {
twoPathGraph(g, 200000, 100000)
},
amt: 70000,
expectedAttempts: 2,
expectedSuccesses: []expectedHtlcSuccess{},
expectedFailure: true,
maxShards: 1,
},
// Test that an attempt is made to split the payment in multiple parts
// that all use the same route if the full amount cannot be sent in a
// single htlc. The sender is effectively probing the receiver's
// incoming channel to see if it has sufficient balance. In this test
// case, the endeavour fails.
{
name: "one path split",
graph: onePathGraph,
amt: 70000,
expectedAttempts: 7,
expectedSuccesses: []expectedHtlcSuccess{
{
amt: 35000,
chans: []uint64{chanSourceIm1, chanIm1Target},
},
{
amt: 8750,
chans: []uint64{chanSourceIm1, chanIm1Target},
},
},
expectedFailure: true,
maxShards: 1000,
},
// Test that no attempts are made if the total local balance is
// insufficient.
{
name: "insufficient total balance",
graph: func(g *mockGraph) {
twoPathGraph(g, 100000, 500000)
},
amt: 300000,
expectedAttempts: 0,
expectedFailure: true,
maxShards: 10,
},
}
// TestMppSend tests that a payment can be completed using multiple shards.
func TestMppSend(t *testing.T) {
for _, testCase := range mppTestCases {
testCase := testCase
t.Run(testCase.name, func(t *testing.T) {
testMppSend(t, &testCase)
})
}
}
func testMppSend(t *testing.T, testCase *mppSendTestCase) {
ctx := newIntegratedRoutingContext(t)
g := ctx.graph
testCase.graph(g)
ctx.amt = lnwire.NewMSatFromSatoshis(testCase.amt)
attempts, err := ctx.testPayment(testCase.maxShards)
switch {
case err == nil && testCase.expectedFailure:
t.Fatal("expected payment to fail")
case err != nil && !testCase.expectedFailure:
t.Fatal("expected payment to succeed")
}
if len(attempts) != testCase.expectedAttempts {
t.Fatalf("expected %v attempts, but needed %v",
testCase.expectedAttempts, len(attempts),
)
}
assertSuccessAttempts(t, attempts, testCase.expectedSuccesses)
}
// expectedHtlcSuccess describes an expected successful htlc attempt.
type expectedHtlcSuccess struct {
amt btcutil.Amount
chans []uint64
}
// equals matches the expectation with an actual attempt.
func (e *expectedHtlcSuccess) equals(a htlcAttempt) bool {
if a.route.TotalAmount !=
lnwire.NewMSatFromSatoshis(e.amt) {
return false
}
if len(a.route.Hops) != len(e.chans) {
return false
}
for i, h := range a.route.Hops {
if h.ChannelID != e.chans[i] {
return false
}
}
return true
}
// assertSuccessAttempts asserts that the set of successful htlc attempts
// matches the given expectation.
func assertSuccessAttempts(t *testing.T, attempts []htlcAttempt,
expected []expectedHtlcSuccess) {
successCount := 0
loop:
for _, a := range attempts {
if !a.success {
continue
}
successCount++
for _, exp := range expected {
if exp.equals(a) {
continue loop
}
}
t.Fatalf("htlc success %v not found", a)
}
if successCount != len(expected) {
t.Fatalf("expected %v successful htlcs, but got %v",
expected, successCount)
}
}