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lnd: buffer upstream/downstream channels for htlc managers

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This commit is contained in:
Olaoluwa Osuntokun 2016-07-21 16:53:07 -07:00
parent 2bb65a3fb8
commit c0a28e3b7f
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1 changed files with 4 additions and 4 deletions
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8
peer.go
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@ -231,12 +231,12 @@ func (p *peer) loadActiveChannels(chans []*channeldb.OpenChannel) error {
// Register this new channel link with the HTLC Switch. This is
// necessary to properly route multi-hop payments, and forward
// new payments triggered by RPC clients.
downstreamLink := make(chan *htlcPacket)
downstreamLink := make(chan *htlcPacket, 10)
plexChan := p.server.htlcSwitch.RegisterLink(p,
dbChan.Snapshot(), downstreamLink)
// TODO(roasbeef): buffer?
upstreamLink := make(chan lnwire.Message)
upstreamLink := make(chan lnwire.Message, 10)
p.htlcManagers[chanPoint] = upstreamLink
p.wg.Add(1)
go p.htlcManager(lnChan, plexChan, downstreamLink, upstreamLink)
@ -579,14 +579,14 @@ out:
// Now that the channel is open, notify the Htlc
// Switch of a new active link.
chanSnapShot := newChan.StateSnapshot()
downstreamLink := make(chan *htlcPacket)
downstreamLink := make(chan *htlcPacket, 10)
plexChan := p.server.htlcSwitch.RegisterLink(p,
chanSnapShot, downstreamLink)
// With the channel registered to the HtlcSwitch spawn
// a goroutine to handle commitment updates for this
// new channel.
upstreamLink := make(chan lnwire.Message)
upstreamLink := make(chan lnwire.Message, 10)
p.htlcManagers[chanPoint] = upstreamLink
p.wg.Add(1)
go p.htlcManager(newChan, plexChan, downstreamLink, upstreamLink)