routing: improve equal cost route comparison
When the (virtual) payment attempt cost is set to zero, probabilities are no longer a factor in determining the best route. In case of routes with equal costs, we'd just go with the first one found. This commit refines this behavior by picking the route with the highest probability. So even though probability doesn't affect the route cost, it is still used as a tie breaker.
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@ -73,6 +73,11 @@ func (d *distanceHeap) Len() int { return len(d.nodes) }
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//
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// NOTE: This is part of the heap.Interface implementation.
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func (d *distanceHeap) Less(i, j int) bool {
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// If distances are equal, tie break on probability.
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if d.nodes[i].dist == d.nodes[j].dist {
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return d.nodes[i].probability > d.nodes[j].probability
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}
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return d.nodes[i].dist < d.nodes[j].dist
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}
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@ -493,13 +493,25 @@ func findPath(g *graphParams, r *RestrictParams, cfg *PathFindingConfig,
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int64(cfg.PaymentAttemptPenalty),
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)
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// If the current best route is better than this candidate
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// route, return. It is important to also return if the distance
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// is equal, because otherwise the algorithm could run into an
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// endless loop.
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// If there is already a best route stored, compare this
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// candidate route with the best route so far.
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current, ok := distance[fromVertex]
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if ok && tempDist >= current.dist {
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return
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if ok {
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// If this route is worse than what we already found,
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// skip this route.
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if tempDist > current.dist {
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return
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}
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// If the route is equally good and the probability
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// isn't better, skip this route. It is important to
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// also return if both cost and probability are equal,
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// because otherwise the algorithm could run into an
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// endless loop.
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probNotBetter := probability <= current.probability
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if tempDist == current.dist && probNotBetter {
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return
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}
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}
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// Every edge should have a positive time lock delta. If we
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@ -2154,6 +2154,72 @@ func testProbabilityRouting(t *testing.T, p10, p11, p20, minProbability float64,
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}
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}
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// TestEqualCostRouteSelection asserts that route probability will be used as a
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// tie breaker in case the path finding probabilities are equal.
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func TestEqualCostRouteSelection(t *testing.T) {
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t.Parallel()
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// Set up a test graph with two possible paths to the target: via a and
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// via b. The routing fees and probabilities are chosen such that the
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// algorithm will first explore target->a->source (backwards search).
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// This route has fee 6 and a penality of 4 for the 25% success
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// probability. The algorithm will then proceed with evaluating
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// target->b->source, which has a fee of 8 and a penalty of 2 for the
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// 50% success probability. Both routes have the same path finding cost
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// of 10. It is expected that in that case, the highest probability
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// route (through b) is chosen.
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testChannels := []*testChannel{
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symmetricTestChannel("source", "a", 100000, &testChannelPolicy{}),
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symmetricTestChannel("source", "b", 100000, &testChannelPolicy{}),
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symmetricTestChannel("a", "target", 100000, &testChannelPolicy{
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Expiry: 144,
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FeeBaseMsat: lnwire.NewMSatFromSatoshis(6),
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MinHTLC: 1,
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}, 1),
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symmetricTestChannel("b", "target", 100000, &testChannelPolicy{
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Expiry: 100,
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FeeBaseMsat: lnwire.NewMSatFromSatoshis(8),
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MinHTLC: 1,
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}, 2),
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}
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ctx := newPathFindingTestContext(t, testChannels, "source")
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defer ctx.cleanup()
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alias := ctx.testGraphInstance.aliasMap
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paymentAmt := lnwire.NewMSatFromSatoshis(100)
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target := ctx.testGraphInstance.aliasMap["target"]
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ctx.restrictParams.ProbabilitySource = func(fromNode, toNode route.Vertex,
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amt lnwire.MilliSatoshi) float64 {
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switch {
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case fromNode == alias["source"] && toNode == alias["a"]:
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return 0.25
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case fromNode == alias["source"] && toNode == alias["b"]:
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return 0.5
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default:
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return 1
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}
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}
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ctx.pathFindingConfig = PathFindingConfig{
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PaymentAttemptPenalty: lnwire.NewMSatFromSatoshis(1),
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}
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path, err := ctx.findPath(target, paymentAmt)
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if err != nil {
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t.Fatal(err)
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}
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if path[1].ChannelID != 2 {
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t.Fatalf("expected route to pass through channel %v, "+
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"but channel %v was selected instead", 2,
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path[1].ChannelID)
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}
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}
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// TestNoCycle tries to guide the path finding algorithm into reconstructing an
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// endless route. It asserts that the algorithm is able to handle this properly.
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func TestNoCycle(t *testing.T) {
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