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routing/test: remove unused parameter in mission control test

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This commit is contained in:
Joost Jager 2019-08-14 14:06:53 +02:00
parent 64c7a0faa8
commit 2594abfba1
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GPG Key ID: A61B9D4C393C59C7
1 changed files with 7 additions and 18 deletions
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25
routing/missioncontrol_test.go
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@ -103,8 +103,8 @@ func (ctx *mcTestContext) expectP(amt lnwire.MilliSatoshi, expected float64) {
}
// reportFailure reports a failure by using a test route.
func (ctx *mcTestContext) reportFailure(t time.Time,
amt lnwire.MilliSatoshi, failure lnwire.FailureMessage) {
func (ctx *mcTestContext) reportFailure(amt lnwire.MilliSatoshi,
failure lnwire.FailureMessage) {
mcTestRoute.Hops[0].AmtToForward = amt
@ -127,10 +127,7 @@ func TestMissionControl(t *testing.T) {
ctx.expectP(1000, 0.8)
// Expect probability to be zero after reporting the edge as failed.
ctx.reportFailure(
testTime, 1000,
lnwire.NewTemporaryChannelFailure(nil),
)
ctx.reportFailure(1000, lnwire.NewTemporaryChannelFailure(nil))
ctx.expectP(1000, 0)
// As we reported with a min penalization amt, a lower amt than reported
@ -143,10 +140,7 @@ func TestMissionControl(t *testing.T) {
// Edge fails again, this time without a min penalization amt. The edge
// should be penalized regardless of amount.
ctx.reportFailure(
ctx.now, 0,
lnwire.NewTemporaryChannelFailure(nil),
)
ctx.reportFailure(0, lnwire.NewTemporaryChannelFailure(nil))
ctx.expectP(1000, 0)
ctx.expectP(500, 0)
@ -160,10 +154,7 @@ func TestMissionControl(t *testing.T) {
// A node level failure should bring probability of every channel back
// to zero.
ctx.reportFailure(
ctx.now, 0,
lnwire.NewExpiryTooSoon(lnwire.ChannelUpdate{}),
)
ctx.reportFailure(0, lnwire.NewExpiryTooSoon(lnwire.ChannelUpdate{}))
ctx.expectP(1000, 0)
// Check whether history snapshot looks sane.
@ -186,16 +177,14 @@ func TestMissionControlChannelUpdate(t *testing.T) {
// Report a policy related failure. Because it is the first, we don't
// expect a penalty.
ctx.reportFailure(
ctx.now, 0,
lnwire.NewFeeInsufficient(0, lnwire.ChannelUpdate{}),
0, lnwire.NewFeeInsufficient(0, lnwire.ChannelUpdate{}),
)
ctx.expectP(0, 0.8)
// Report another failure for the same channel. We expect it to be
// pruned.
ctx.reportFailure(
ctx.now, 0,
lnwire.NewFeeInsufficient(0, lnwire.ChannelUpdate{}),
0, lnwire.NewFeeInsufficient(0, lnwire.ChannelUpdate{}),
)
ctx.expectP(0, 0)
}