peer.go: moving the apply function outside of the constructor

This is mainly for readability so that the function isn't indented.
This commit is contained in:
nsa 2020-06-26 21:07:00 -04:00
parent 4ee4a1a24e
commit 02fd905f61

52
peer.go

@ -1060,35 +1060,37 @@ func newChanMsgStream(p *peer, cid lnwire.ChannelID) *msgStream {
var chanLink htlcswitch.ChannelLink
apply := func(msg lnwire.Message) {
// This check is fine because if the link no longer exists, it will
// be removed from the activeChannels map and subsequent messages
// shouldn't reach the chan msg stream.
if chanLink == nil {
chanLink = waitUntilLinkActive(p, cid)
// If the link is still not active and the calling function
// errored out, just return.
if chanLink == nil {
return
}
}
// In order to avoid unnecessarily delivering message
// as the peer is exiting, we'll check quickly to see
// if we need to exit.
select {
case <-p.quit:
return
default:
}
chanLink.HandleChannelUpdate(msg)
}
return newMsgStream(p,
fmt.Sprintf("Update stream for ChannelID(%x) created", cid[:]),
fmt.Sprintf("Update stream for ChannelID(%x) exiting", cid[:]),
1000,
func(msg lnwire.Message) {
// This check is fine because if the link no longer exists, it will
// be removed from the activeChannels map and subsequent messages
// shouldn't reach the chan msg stream.
if chanLink == nil {
chanLink = waitUntilLinkActive(p, cid)
// If the link is still not active and the calling function
// errored out, just return.
if chanLink == nil {
return
}
}
// In order to avoid unnecessarily delivering message
// as the peer is exiting, we'll check quickly to see
// if we need to exit.
select {
case <-p.quit:
return
default:
}
chanLink.HandleChannelUpdate(msg)
},
apply,
)
}